I searched to insert image into sql database from c# form..TRied for a long days..Every efforts was use less...
But I NEVER GIVEUP....worked hard and found the solution baby...It is like dat...I m explain it..
This picture box will only displays the image you are going to
save in your database providing some id in the textbox (I used this to
just recall the image from database) once an image is loaded on the
clicking event of Store button we are going to insert that image with
provided ID into the database and the combo box will load itself with
all available IDs in our database. By selecting an id we and clicking
Retrieve the respective image will be shown in the second picture box.
So, now right click on your form and select view code.
Here declare a global string
a data adapter
and a dataset
you will also require to use System.IO and System.Data.SqlClient
using System.IO;
using System.Data.SqlClient;
now we need to create a method to insert our image into the database
and second method to retrieve all images. I named the method inserting
my image into the database as update() and to retrieve my images I named my method as connection().
Now update() uses filestream to convert the image into binary data
since image datatype in SQL Server 2005 use to store binary data in its
image datatype. While connection() simply convert that binary data to
an image using identical technique for us. Code for both the methods is:
private void updatedata()
{
//use filestream object to read the image.
//read to the full length of image to a byte array.
//add this byte as an oracle parameter and insert it into database.
try
{
//proceed only when the image has a valid path
if (imagename != "")
{
FileStream fs;
fs = new FileStream(@imagename, FileMode.Open, FileAccess.Read);
//a byte array to read the image
byte[] picbyte = new byte[fs.Length];
fs.Read(picbyte, 0, System.Convert.ToInt32(fs.Length));
fs.Close();
//open the database using odp.net and insert the data
string connstr = @"Data Source=.;Initial Catalog=TestImage;
Persist Security Info=True;User ID=sa";
SqlConnection conn = new SqlConnection(connstr);
conn.Open();
string query;
query = "insert into test_table(id_image,pic) values(" +
textBox1.Text + "," + " @pic)";
SqlParameter picparameter = new SqlParameter();
picparameter.SqlDbType = SqlDbType.Image;
picparameter.ParameterName = "pic";
picparameter.Value = picbyte;
SqlCommand cmd = new SqlCommand(query, conn);
cmd.Parameters.Add(picparameter);
cmd.ExecuteNonQuery();
MessageBox.Show("Image Added");
cmd.Dispose();
conn.Close();
conn.Dispose();
Connection();
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
//----------------------------------------
private void Connection()
{
//connect to the database and table
//selecting all the columns
//adding the name column alone to the combobox
try
{
string connstr = @"Data Source=.;Initial Catalog=TestImage;
Persist Security Info=True;User ID=sa";
SqlConnection conn = new SqlConnection(connstr);
conn.Open();
empadap1 = new SqlDataAdapter();
empadap1.SelectCommand = new SqlCommand("SELECT * FROM test_table"
, conn);
dset = new DataSet("dset");
empadap1.Fill(dset);
DataTable dtable;
dtable = dset.Tables[0];
comboBox1.Items.Clear();
foreach (DataRow drow in dtable.Rows)
{
comboBox1.Items.Add(drow[0].ToString());
comboBox1.SelectedIndex = 0;
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
now double click the Load button and write the code lines:
try
{
FileDialog fldlg = new OpenFileDialog();
//specify your own initial directory
fldlg.InitialDirectory = @":D\";
//this will allow only those file extensions to be added
fldlg.Filter = "Image File (*.jpg;*.bmp;*.gif)|*.jpg;*.bmp;*.gif";
if (fldlg.ShowDialog() == DialogResult.OK)
{
imagename = fldlg.FileName;
Bitmap newimg = new Bitmap(imagename);
pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage;
pictureBox1.Image = (Image)newimg;
}
fldlg = null;
}
catch (System.ArgumentException ae)
{
imagename = " ";
MessageBox.Show(ae.Message.ToString());
}
catch (Exception ex)
{
MessageBox.Show(ex.Message.ToString());
}
Now double click Store button and call the update () method to insert selected image into the database.
the update method itself calls connection() therefore combo box will
be filled with IDs of images exits in database, one can use the
connection method in anyway the person likes.
Finally double click Retrieve button and write
DataTable dataTable = dset.Tables[0];
//if there is an already an image in picturebox, then delete it
if (pictureBox2.Image != null)
{
pictureBox2.Image.Dispose();
}
//using filestream object write the column as bytes and store
it as an image
FileStream FS1 = new FileStream("image.jpg", FileMode.Create);
foreach (DataRow dataRow in dataTable.Rows)
{
if (dataRow[0].ToString() == comboBox1.SelectedItem.ToString())
{
byte[] blob = (byte[])dataRow[1];
FS1.Write(blob, 0, blob.Length);
FS1.Close();
FS1 = null;
pictureBox2.Image = Image.FromFile("image.jpg");
pictureBox2.SizeMode = PictureBoxSizeMode.StretchImage;
pictureBox2.Refresh();
}
}
Thats my way...Try it and tell about it...If you dont like dont doooo...scooby duby dooooooooo
Visit Srilanka...Its my beautiful country
CraZy Programmer
Rajitha Anuradha
rajithasomarathna@gmail.com
